/*Please explain the output, output is 12 11 1*/

Question

#include <stdio.h>

int main() { int a[5]={5,10,15,20,25};
int i,j,k=1,m;
i=++a[1];
j=a[1]++;
m=a[i++];
printf ("\n%d %d %d",i,j,m);
return 0;
}

Answer 1

i = 1, ++1 makes 2, 2 + a[1] equals 12
j = a[1] ++ makes 10 + 1 equals 11
m= a[13] , this is out if bound so the initialen value 1 is printed

Would expert a out of bound exception, do not know why that's is geen as valide.

Answer 2

you mean i=[++a1] is not initialization? and i still==0 after that, right?

Answer 3

@~ swim ~
I have to admit you are right. Thanks for pointing it out.

Answer 4

so I don't get one thing. why is m == 1 in the end if m = a[i++] and i = 11? is it realy random?

Answer 5

thank you)