if 1 + 1 * 3 == 6 print ("Yes") else : print ("No")

Question

Im getting invalid output

Answer 1

Normally, the operator precedence is this: parenthesis, multiplication, division, modulus, addition and subtraction

1 + 1 * 3 = 4
1 + ( 1 * 3 ) = 4
( 1 + 1 ) * 3 = 6

Answer 2

That's an invalid syntax. You're missing a colon (:) after 6.

Answer 3

like that?

Answer 4

I get it now

Answer 5

thanks y'all

Answer 6

Just check the precedent at first.
Parantheses >exponentiation > multiplication/division > addition/ subtraction.
It's shown the value is not true, so extract to No

Answer 7

okay

Answer 8

it's still the same

Answer 9

if (1+1*3==6)
{
print ("yes") ;
}

else :
{
print ("no") ;
}

Answer 10

still error

Answer 11

As Dev said, you're missing a colon, it should be like this:

if ( 1 + 1 ) * 3 == 6:
// do stuff

Answer 12

like this one??

Answer 13

multiplication is executed first .... in order to add 1 to 1 first , and then multiple the result by 3 u must put the addition in ()

Answer 14

if( (1+1) * 3 ==6) {

bla bla bla
}

Answer 15

Expanding on what noname said.

Here's an article on Operator Precedence:
https://en.wikipedia.org/wiki/Order_of_operations

Answer 16

No, multiplication, add, equal

Answer 17

Because the first it is multipluing

Answer 18

Elisha Miracle

if 1 + 1 * 3 == 6 :
print ("Yes")
else :
print ("No")

Answer 19

What is the result of this code?

if 1 + 1 * 3 == 6:
print("Yes")
else:
print("No")

Answer 20

What is the result of this code?

if 1 + 1 * 3 == 6:
print("Yes")
else:
print("No")