Please heeeeelp

Question

X=2 , y=4
Y*=2
X=y++ - ++y
X++
Printf(x and y)
What is x and y!!!?

Answer 1

Actually:
x = undefined,
y = 6,
C is case-sensitive. That means X is not x. Y is not y.
^Kidding, but be careful all the same when posting code.
PS: printf("%d\n%d\n", x, y); is what you're looking for.

Ace Aren't mathematics pre-calculated and converted to literals where relevant values are known at compile-time by all compilers? Just curiosity, I'd still never rely on that behaviour.

Answer 2

the first y++, means use the value of y, and THEN increment it by 1.

++y means increment it by 1, and THEN use it.

y=8 just before the x=y++ - ++y line.

That line with the y++ etc, therefore is really this:

x = value of y (but then increment y by 1) - (increment y by 1) value of y

x = 8 - 10 [and now y is 2 higher]

Answer 3

nonzyro Definitely agree. That's why I said "if ignoring compilation errors" ☺ It's almost doable as some kind of C pseudo-code 🤕🙃

Answer 4

Xan Actually it reminds me of a Natural Language dialect of Basic a friend proposed for teaching kids to program. I said stick to Lego.

Answer 5

X=2 , y=4
Y*=2 // y=8
X=y++ - ++y // X=-2, y=10
X++ // X=-1
Printf(x and y)
What is x and y!!!?

x=-1
y=10

If ignoring compilation errors!

Answer 6

I need to Know something when i delete x++ then x=-2 hoow

Answer 7

Thhhhhhhanks so freaking much

Answer 8

Yes I know this .. just it's the keyboard phone