Encryption : Rotate 3

Question

i want to transform a letter from the alphabet to another one ( that other one is the letter who's after the first letter by 3) e.g. letter 'a' becomes 'd' and 'b' becomes 'e'... i do have an idea for how to do this but instead of the letter being transformed to the letter i only get the ascii code of that number... any help will be appreciated!

Answer 1

because probably u r not casting .
suppose ur character is 'a' then u should weite simply
'a' +3 for d but here u r doing one mistake.
as 3 is int whole expression will get coverted to ascii /int value of d.
to make it character again typecast it like (char)('a'+3)

Answer 2

thanks mate it worked :)

Answer 3

bro i dont know c#😞
but i suggest u one thing
write -
(char)(ch+(3+ch-'a' )%26 );
this one line will shorten ur code