This is printing 1st row only and not slicing it to the given number of rows. Please help!

Question

#define a function to print the matrix
def matrix_print(matrix, x, y):
#matrix_print(matrix, rows, columns)
a = 0
for m in range(x):
n=y
print(matrix[a:n])
if n == y+1:
a=y+1
n=y*2

Answer 1

cannot copy to code playground but at first glance it seems that you iterate only the colums in the first row. you do need two cycles nested.

Answer 2

#define a function to print the matrix
def matrix_print(matrix, x, y):
#matrix_print(matrix, rows, columns)
a = 0
for m in range(x):
n=y
print(matrix[a:n])
if n == y+1:
a=y+1
n=y*2

def matrix_input():
#take matrix input
#define the matrix
matrix = []
#take the no. of rows in the matrix
i = float(input("Please enter the number of rows in the matrix : "))
#check if the input is correct for rows
if i%1 != 0:
i = int(i)
print("Wrong input! : Decimal converted to integer")
i = int(i)
j = float(input("Please enter the number of rows in the matrix : "))
#check if the input is correct for columns
if j%1 != 0:
j = int(i)
print("Wrong input! : Decimal converted to integer")
j = int(j)
#take input using loop
m = 0
n = 0
#define the loop
for m in range(i):
#this loop is for rows
for n in range(j):
#this loop is for columns
str = "Enter the elemnt of row {x} column {y} : ".format(x=m+1,y=n+1)
k = float(input(str))
matrix.append(k)
matrix_print(matrix, i, j)

matrix_input()

This is the complete code

Answer 3

Please help

Answer 4

Good