code analysis (errors?)

Question

#include <stdio.h>

int main(void)
{
int a,b,s;
char o;

printf("Primeiro numero: ");
scanf("%d",&a);

printf("Operador:");
scanf("%c",&o);

printf("Segundo numero: ");
scanf("%d",&b);

if (o=='+') {
s = a + b;
printf("O resultado é: %d\n",s);
}

else if (o=='-') {
s = a - b;
printf("O resultado é: %d\n",s);
}

else if (o=='/') {
s = a / b;
printf("O resultado é: %d\n",s);
}
else if (o=='*') {
s = a * b;
printf("O resultado é: %d\n",s);
}
else {
printf ("Erro!!!!!!!!");
}
return 0;
}

Answer 1

It happens,no worries .. Akib Reza

Answer 2

Code is working for me .
Just neither change line nor give any space between the inputs .
Give it like 7*4 not like 7 * 4 .

Answer 3

Akib Reza Double quotes will throw errors .Try compiling ur solution .

Answer 4

Yah, got it. Thanks ishan i forgot.(Haven't coded cpp in a while)

Answer 5

the error is with the compiler, because when giving enter to send the input data he interpreted the enter as the "operador", just put a scanf before the scanf of the "operador", but thanks for the tips

Answer 6

😂😂 Ok. Have fun.

Answer 7

Is that at school they use compilers online :( Thanks for the attention people.