How did the output of this program become 1????

Question

#include<iostrem.h>
Using namespace std;
Int main()
{
Cout<<(0==0)
}

Answer 1

0 is equal to 0, right
so the expression 0==0 is true and returns "1", which is displayed by cout

if it was 0==1, answer would be "0", cause 0 is not equal to 1

Answer 2

the condition within the brackets is checked, which is true
in c++, "1" represents true and "0" represents false
so your program returns 1

Answer 3

the condition is boolean, true meens 1 and false 0(does 0 equals 0)

Answer 4

Trying to printing booleans and conditions will print 1 if the bool or condition is true otherwise 0

Answer 5

Thanks for clarify my doubts sreejith

Answer 6

see 0==0 evaluating to 1 because this expression is true the (==) matches the l-value to r-value and there l-value and r-value are equal

Answer 7

Thank you aveek

Answer 8

How was it true???
Plz explain breafly...

Answer 9

it is a logical expression which evaluates to true or false . When we say say the logical expression is true , the expression returns 1 and When we say say the logical expression is false , the expression returns 0

Answer 10

if you want your result to be false
then -

#include <iostream>
using namespace std;

int main() {
int x=0;
if(x)
{
cout << 1;
}
else
{
cout << 0;
}
return 0;
}