Why Is this type conversion don't give output

Question

main()
{
int i=7;
char p;
p=(char)i;
printf("%c",p);
}

Answer 1

your code hasn't error.. just think you give 7 and type-cast to char and on 7 ascii value no digit.. use i=65 and see its print A
https://www.asciitable.com/ consider this link for ascii list visualmedia ytb

Answer 2

your code also convert int 7 to char 7 but char 7 has no visual digit that's why it doesn't show in printf.

Answer 3

thanks mahn.... 😘😘😘

Answer 4

bt the way how can i convert int 7 to char '7'???