Why is the output 5 and not p2?

Question

int a=5;
int *p1 = &a;
int **p2 = &p1;
int ***p3 = & p2;
cout << ***p3;

Answer 1

Out put is 5 because:

Firstly, p3 points to p2
Then, p2 points to p1
Then, p1 points to a
Lastly, a is equal to 5

so p3 is also equal to 5

The ‘&’ symbol is a pointer used to point to a space

p3 points all the way to a which is equal to 5

Answer 2

I think before understanding the output you should understand "what is pointers?"
https://www.sololearn.com/learn/CPlusPlus/1630/