Questions like x++ + ++x - --x

Question

it is hard to figure out ! I know that x++ gives no effect but pre operator are hard

Answer 1

1. x++ means first use the value of x and then increment the value of x by 1.
2. ++x means to first increment the value of x by one and then use it .
3. same goes with x-- and --x respectively but in this case the value would be decremented.
Now,
for ex:- if we take the value of x to be 5,
we have to solve the code from left to right always and keep check of operator precedence,
so ,
placing the value of x as 5,
0. x++ + ++x - --x
1. 5++ + ++x - --x, the value of x is 5 but it is incremented to become 6
2. 5 + ++6 - --x, the value of x is first incremented to become 7
3. 5 + 7 - --7, the value of x is first decremented to again become 6
4. 5 + 7 - 6 = 6 ( answer)
compiler would take it as,
5. 5++ + ++6 - --7;
( x becomes 6 in second expression ++6because the original value 5 has been use in the first expression and then incremented)
( x becomes 7 in the third expression because in second expression it has been incremented and latter in the third it has been decrement to make it finally 6)

Answer 2

i have changed the answer please read it again with a cool mind