what is the C++ code doing?

Question

int* ptr = new int(27);
*ptr = 34;
...
delete ptr;

so
1. ptr is a pointer with a value 27
2. value at ptr is changed to 34
3. delete ptr

Answer 1

You're right. If you write cout << ptr; after the delete ptr; instruction, you'll get the place of the pointer in the memory, like 0x681640, or 0x351640 (check this code: https://code.sololearn.com/cZb0fb74VU11/?ref=app).

Answer 2

yeee! ... I'm abit confused about this part

*ptr=34;

I thought it's changing value at ptr to 34.when I do

cout << *ptr <<endln;

the value is 8327888