Is there any other way to solve this without calling "mean()" function twice in 8th no line?

Question

https://code.sololearn.com/c6Mj2rTAc9wM/?ref=app

Answer 1

You can calculate all the means first:

means = [(name, mean(scores)) for (name, scores) in input.items()]

and then get the biggest mean with the max function:

maximum = max(means, key=lambda x: x[1])

Answer 2

https://code.sololearn.com/cEE4CcoU7WNP/?ref=app

you pay with memory space

Answer 3

Sayan Kundu no prob!
all students with highscore are printed

Answer 4

This is the best I can do, though it's still probably not quite what you wanted :(

https://code.sololearn.com/cKC3Lr8XfKFf/?ref=app

Edited code to my actual attempt. For some reason, my saved code was identical to yours Sayan Kundu !

Answer 5

Schindlabua Oma Falk But, in the input dictionary more than one student have highest score. So the output could be a list of multiple names.

Answer 6

I can construe this into a oneliner but it is just bad practice.

https://code.sololearn.com/cNmGjIS5YaHN/?ref=app

Answer 7

New attempt - one liner and one usage of "mean()".

https://code.sololearn.com/c5z0wDpbHrYW/?ref=app

It's just that using 'eval()' is generally considered bad practice.

Answer 8

what does return do again?