The output is coming out to be an error...is that because the operation that i performed is illegal?

Question

https://code.sololearn.com/c628l5R6xAln/?ref=app

Answer 1

You are attempting to add an integer to a string using the operator ‘+’. To print your string and the integer 1, you would use cout << a << 1;

Answer 2

Because there's no match for + operator when one operand is a string ( char sequence ) and other is an int constant. Technically, you are attempting to add this

a:
| I | | a | m | | l | e | a | r | n | i | n | g | | C | + | + |

with this constant

1

So, how the heck should the compiler know what to do?
On the other hand, picking one character from the char sequence and adding 1 to it isn't illegal at all. So,

a[a.length() - 3] + 1;

| I | | a | m | | l | e | a | r | n | i | n | g | | C | + | + |
^
+1

would turns the initial string to

"I am learning D++"

Answer 3

this not a java comiler to add a string using + operator only this is possible in your code cout<<a<<1; then your output is i am a learning in c++1 thats it