how to count character in the row and column that doesn't have 'a' character

Question

for example input=
bbba
babb
bbbb

output=8

input=
12a3
1234
1234
12a3

output= 14

//note= the number that had already be counted in the row can't be counted again in the column

Answer 1

Something like this
https://code.sololearn.com/cXPRpK0d2eT1/?ref=app

Answer 2

I'd have two matrices: the input and a boolean. Set the booleans to false. For each row and column, if there isn't an a in it, set the corresponding booleans to true. Count the trues.

Answer 3

For each 'a' we need to exclude corresponding row and column.
The answer is character count in the not excluded rows + in the not excluded columns - their intersection (nerow*necolumn).

Answer 4

Your example incorrect. Second variant should out 14

Answer 5

sorry, can someone give me the example code? because i still don't understand about this

Answer 6

oh thats true hahaha... thanks for the correction