Is there any way to pass in multiple conditions for a while loop without using a nested if statement? (see lines 31 to 36)

Question

https://code.sololearn.com/cj3OMBOg93Ne/?ref=app

Answer 1

while m[:-4:-1][::-1] not in (user, cpu):
m.append(randint(0, 1))
wins += m[:-4:-1][::-1] == cpu

Answer 2

Maybe

while True:
if m[:-4:-1][::-1] in [user, cpu]:
wins += m[:-4:-1][::-1] == cpu
break
m.append(randint(0, 1))

I can't test it because code playground seems to be down again

Answer 3

yes you can, using and

while condA and condB

Answer 4

correct me if im wrong
but you need to break the loop if the condition are true right ? did you change == to != ?

while m[:-4:-1][::-1] != user or m[:-4:-1][::-1] != cpu:
if m[:-4:-1][::-1] == cpu:
wins += 1
break

Answer 5

Mert Yazici That worked!! Thanks a lot

Answer 6

Anna That works! How did this not occur to me! Anyway thanks a lot!!

Answer 7

It doesn't change a whole lot, but could you connect your two ifs with or? Then you have only one break case...

Answer 8

HonFu That is what I did earlier. But I changed it just to increment the wins counter in lesser number of lines. Thanks for the input though😊👍

Answer 9

but that doesn't work for me as I need to use or.
Even then, that syntax doesn't work

Answer 10

Taste You are right. For the conditions on the while loop, I do have to use !=. But for me two. conditions in the while loop makes it an infinite loop. that never matches a condition.