What does the swap function mean? How does it work?

Question

void swap(int *a, int *b) {
int temp = *a;
*a = *b;
*b = temp;
}

Answer 1

instead of swapping original values you are working on the address of those values meaning swapping them using pointers ,so you are actually swapping the values here

Answer 2

it swaps the values of a and b by using the third variable temp
first temp=a then
a=b then
b=temp
first temp got the value of a then a is assign with the new value of b

Answer 3

Abhay, we are working with values of variables. Adress are not swapped. In this case, when we use swap(x, y) adresses of x and y are not changed but values are.