How can i convert char to int in C/C++ ?

Question

I am trying to convert char to int in the following example but nothing works , please anyone

char ch1 = '5' ,ch2='6';
int a=(int)ch1 + (int)ch2;
cout<<a;
// output should be 11

/*
thanks in advance

Answer 1

here's a little trick that'll get it done...
char x='12';
int y=x-'0';
Now y stores x's value as an integer...

Answer 2

You can also do this:

char c1 = '5', c2 = '6' ;
int sum = (c1 - '0') + (c2 - '0') ;

But Anna's solution is way more easier to implement.

Answer 3

By defining 5 and 6 as integers, not as chars '5' and '6'. Or you can remove the quotation marks: char a = 5, b = 6. Then a will be set to the char with the ASCII value 5 (whatever ASCII char that may be)

Answer 4

thanks Tyrant that's what i was looking for

Answer 5

Remove the quotation marks

Answer 6

Anna thanks it worked

Answer 7

(int)char will return the ASCII value of the char, not the number that the char represents. The ASCII value of '5'/'6' is 53/54, their sum is 107 and that's the value that is assigned to a.

Answer 8

Anna But i want 11 as output..by adding 5 and 6. How can i get that?

Answer 9

Anna that's okay, But my problem is that if those values are stored in a char datatype then what will be the approach?

Answer 10

Nice! You're welcome 😃