Why there is a size difference between calling a parameterized array and calling?

Question

Actually I've seen that, when I try to define an array it's better to allocate the size after defining the index size. So, to define the size that way I wrote this...

#include<bits/stdc++.h>
using namespace std;
main()
{
int *array,size;
cout<<"The size of the array pointer: "<<sizeof(array)<<endl;
cout<<"Enter the size of your array: ";
cin>>size;
array=new int[size];
cout<<"The size of the array pointer: "<<sizeof(array)<<endl;
// During the compilation the above line of code is ignored & won't shown in the Console.
cout<<"Enter elements:"<<endl;
for(int i=0;i<size;i++)
{
cin>>array[i];
}
cout<<"Your array: ";
for(int i=0;i<size;i++)
{
cout<<array[i]<<" ";
}
cout<<endl<<"The size of the array pointer: "<<sizeof(array)<<endl;
}

But, from the beginning the size of the array shows 8 Bytes, while each integer takes 4 bytes of memory. I've no problem while storing an array of any size. It works as same as a parameterized array. But, my question is why it took only 8 bytes of memory?

Answer 1

https://stackoverflow.com/questions/492384/how-to-find-the-sizeof-a-pointer-pointing-to-an-array

8 bytes is of that address of that pointer and not the total memory pointed by that pointer