Is there a method which removes all of the same elements from a list at once in python?

Question

For example,
list = ["a", "b", "c", "b", "b", "d"]

How can I remove all of the "b"s?

The easiest way I can think of, for now, is

list = ["a", "b", "c", "b", "b", "d"]
new_list = [x for x in list if x != "b"]

Is there a method or a better way than this one?

(I searched for similar questions, but I couldn't find any...I'm sorry if this is duplicated.)

Answer 1

Here an solution that might help you
let's say alice is your list

list(filter(("b").__ne__,alice))

Answer 2

Thank you for answering.
But in your way, one "b" still remains.
And if the list is
list = ["a", "b", "c", "b", "c"] ,
then one "c" is also removed.
I don't want other elements to be removed if they are duplicated.

Answer 3

It's ok. Thank you for answering anyway😊

Answer 4

It a rich comparison method
In this , a!=b is written as a.__ne__(b)

Answer 5

I understood✨ Thank you very much for your help😊

Answer 6

Thank you very much😄 It worked!
What is .__ne__?

Answer 7

Bebida Roja
Thank you for answering.
But in your way, one "b" still remains.
And if the list is
list = ["a", "b", "c", "b", "c"] ,
then one "c" is also removed.
I don't want other elements to be removed if they are duplicated.

Answer 8

There's a trick
Say x is your list
print(list(set(x)))

Answer 9

Welcome

Answer 10

just convert the list to a set, although you will have an unordered set.

Answer 11

Ahhh....sorry ways on the way to home...didn't read your question properly
Thought just need to remove duplicates