Please explain the output of the following code

Question

How can we call the destructor, and if we could then why does the object is still usable??

https://code.sololearn.com/c32IWYnwWDvw/?ref=app

Answer 1

The behaviour of the following operations is undefined. There are two things undefined here:

0) Accessing a member object after calling the destructor.
1) Automatic calling of the destructor again upon encounter of } by the compiler.

Anything can happen, ranging from a sucessful run to a segmentation fault.

Read more about things here:

https://isocpp.org/wiki/faq/dtors#dont-call-dtor-on-local

http://en.cppreference.com/w/cpp/language/ub

Answer 2

Because calling destructor manually just executes what's inside it, it won't destroy any object. Destructor will only destroy any object when it is called by compiler.