when function foo(x,y) is called, will not then the value of n assigned to x and that of m to y? Help please!

Question

#include<stdio.h>
void foo(int n,int m) {
n = 11;
m = 93;
//printf("%d %d\n",n,m);
}
int main() {
int x =7, y =4;
foo(x,y);
printf("%d ",x);
printf("%d",y);
return 0;
}

Answer 1

7 and 4 will be output

Because here we are passing bu value
So value of variable x and y will be passed which will be copied in n and m respectively

Once v make change in n and m that won't affect x and y because x and y has different memory address

Answer 2

A hint. Add these lines...

...to foo():
printf("--> n:%x m:%x <--\n", &n, &m);

...to main():
printf("--> x:%x y:%x <--\n", &x, &y);

Output: The addresses of each variable in memory.

Answer 3

...and they have different addresses because 'n' and 'm' are 'local' to foo.

Space is allocated for these local variables on a temporary 'stack' when the function is called, and this memory is released when the function returns.

Answer 4

[redacted] Mason Mixdorf Please don't post spam-like comments and please do review...
https://www.sololearn.com/discuss/321242/?ref=app
https://www.sololearn.com/discuss/1316935/?ref=app