How can l write this number in c++

Question

1
12
123
1234
12345

Answer 1

You can do this with the help of nested loops

It's easy you should try yourself first then look at the solution

Source Code:

for(int i=1 ; i<6 ; i++) {
for(int j=1 ; j<i+1 ; j++) {
cout<<j;
}
cout<<endl;
}

I hope this will help
Thank you

Answer 2

Hi everyone,

you can do it with just one for loop, something like this:

int x = 0;
for (int i = 1; i <= 5; i++) {
x = x * 10 + i;
printf("%d\n", x);
}

Answer 3

Thank you 👌
I will try again

Answer 4

Anas Welcome

Answer 5

very good and easy 👌 ~ swim ~

Answer 6

#include<iostream>
using namespace std;
int main()
{
for(int i=1;i<6;i++){
for(int j=1;j<i+1;j++)
{cout<<j;
}
cout<<endl;
}
}

Answer 7

eduardo g Yes this is true and very good for training .... I love this kind of algorithms and I try to train them

Answer 8

nice!

Answer 9

Mohamed Ghazouly because
I missed 'l' in 'endl'
Thanks for Reporting

Answer 10

Bad_bit
Hey man
Its not working

Answer 11

Anas exactly what i was going to post! if done like the first answer the sequence will be linear, you need a line break for every loop and i tried a couple of ways including putting the //cout<<j<<endl;// but it made the output vertical. These type of exercises helps understand this widely used algorithm.

Answer 12

#include <iostream>
using namespace std;
int main (){

for(int i=1;i <=5;i++){
for (int j=1;j <=5;j++){
if (i>=j)
cout <<j;
else
cout <<" ";
}
cout <<endl;
}
}

Answer 13

#include <iostream>
using namespace std;
int main (){
cout<<'1'<<endl<<"12"<<endl<<"123"<<endl<<"1234"<<endl<<"12345";
return 0;
}

No need for thanks😀😁

Answer 14

#include <iostream>
using namespace std;
int main (){
for (int i=1;i <=5;i++){
for (int j=1;j <=5;j++){
if (i>=j)
cout <<j;
}
cout <<endl;
}
}