Can anyone explain working of this code(dry run)

Question

#include <iostream>
using namespace std;
int main()

{

int array[10],i,num,n,c=0,pos;

cout<<"entr the array size:\n" ;
cin>>n;
cout<<"enter array elements\n";
for(i=0;i<n;i++)
{
cin>>array[i];
}
cout<<"enter no to be searched\n";
cin>>num;
for(i=0;i<n;i++)
{
if (array[i]==num)
{
c=1;
pos=i+1;

break;

}
}
if (c==0)
{
cout<<"no not found";

}
else
{
cout<<num<<"no fond at pos"<<pos;
}

return 0;
}

Answer 1

Dry run to the code of USMAN ZAFER

I have click picture of my notebook
see my post on activity feed above is heading