Why is the size of s[2] 16 here?

Question

#include <stdio.h>
struct student {char *c;};
int main() {
struct student s[2];
printf("%d",sizeof(s));
return 0;
}

Answer 1

Hi there my friend, pardon me, but that was rather incorrect, the reason sizeof(s) returns 16 here is because the struct <student> contains a char pointer, and size of a pointer is generally 8 bytes (assuming in a 64bit system), thus an array of student structure having 2 elements is weighed for 2 * 8 (number of elements [2] multiplied by size of char pointer [8]).

The char type size is actually only 1 byte, check it with sizeof(char).

Regards,

Answer 2

Because, the size of pointer is 8, we multiply it by the size of this array 2 , so: 8*2

edited, thanks to Ipang