Why this code prints 32 ?

Question

#include <stdio.h>

int recurse(int n){
if(n<=1) return 20;
return(3+recurse(n-1));
}

int main() {
printf ("%d", recurse (5));
return 0;
}

Answer 1

recursive(5)=>
3+recursive(4)=>
3+3+recursive(3)=>
...
3+3+3+3+recursive(1)=>
3+3+3+3+20= 32

Answer 2

recurse(5) calls recurse(4)
recurse(4) calls recurse(3)
...
recurse(2) calls recurse(1)
recurse(1) returns 20
recurse(2) now returns 20+3=23
recurse(3) now returns 23+3=26
...
recurse(5) Noe returns 29+3=32
main() method outputs 32.
That's how it works.

Answer 3

The resource function will be invoked until de value of "n" is 1 ande it enters the if (n<=1) so that it returns 20 and ends, since it no longer invokes the function resource.

3+4=7
3+2=5
20

n=7+5+20
n=32

Answer 4

Bro. Thanks for this question. I was stuck asf. Thank you.