loop

Question

Please explain to me, how the output of this:

A=[1,2,3,4,1]
for n in A:
A[n]=0
print(A)

is [0,0,3,0,1] ?

Answer 1

In first iteration,
A[1] becomes 0.
In second iteration,
A[0] becomes 0.
In third iteration,
A[3] becomes 0.
In 4th iteration,
A[0] becomes 0. However, it was 0 before too.
In 5th iteration,
A[1] becomes 0. However, it was 0 before too.

At Last, list A is like :
[0,0,3,0,1]

Answer 2

I’m sorry, I don’t get it :(
Could you please explain this in other way?

Answer 3

Посмотри вот этот код. Добавил выводы для наглядности. Проследи за тем, как меняется массив после каждой итерации
A=[1,2,3,4,1]
for n in A:
print(n)
print(A[n])
A[n]=0
print(A[n])
print(A)

Answer 4

спасибо большое, я разобралась!)