Why does second condition not execute

Question

Help

https://code.sololearn.com/cffQ5vFWz51o/?ref=app

Answer 1

Because the first condition is true. All other else statements will be skipped after a condition is found to be true

Answer 2

"else if" is only executed, when "if" is false.

Since
10 is smaller than 20
and
10 is greater than 6
the "if" is true and no other statement in the "if"-statement are checked.

Please use proper tags:
Included the programming language in the tags.
Do not use unneccessary tags like "help" and "asap"

Answer 3

https://code.sololearn.com/cy6OIsZ3cEQD/?ref=app
Thanks for the help I also have query on the above code.

Answer 4

//sneeze //jay Thank you,guys for helping me out its quite generous of you.
Regarding the double post.I am sorry as I am new to this forum,so I'm not familiar with the protocols.
I respect your decision I will not do that again.

Answer 5

Keep coding. Keep asking. Keep learning. That is why we mention it.

Answer 6

Please start a new thread for every question

if num==3
the code will executes continue;

Continue jumps out of the while and does not decrease num--
So num stays 3

It comes in another iteration and the same repeats.
Here you have created a infinite loops

Personally I do not use continue because of this behaviour.

You can do this with just for-loops, while-loops and if-statement

if (num == 3)
{
num--; //decraese num before continue
continue;
}

I do prefer this one
if (num != 3)
{
printf("%d\n",num);
}