For loop

Question

Print a loop:
0
1
4
9
16

I've got:
for i in range (0,5):
i += (1)
if i % 2 !=0:
print(i)
Any ideas how to increase each loop by an iteration of an odd number? x + 1, then x + 3, then x + 5, etc? Thanks for any help:)).

Answer 1

Diego got it 👍

Answer 2

you could do what i did on this code
https://code.sololearn.com/co3k6QKJHU83/?ref=app

Answer 3

for i in range(x):
print(i**2)

Answer 4

Thanks, Aki:).

That does increase each integer by 1. Now, how do I increase each iterarion by an incramentally higher odd number (first + 1, then x + 3, then x+5, etc.)?

I'll edit my post now to reflect the actual desired outcome. :).

Answer 5

Thanks David and Diego! i've tested it out and it works.

One more question:
It says: print(i**2)
Output: none

As (i**2) is any number times itself why isnt 0 •• 2 achknowledged in this code?

Thanks for help!

Answer 6

Perhaps you included the print statement in an if condition that is never met.The full code would look like this

for i in range(5):
print(i**2)

Answer 7

if so, then maybe this code can help
https://code.sololearn.com/c4On2dbkxWd6/?ref=app

Answer 8

Thanks, Aki! That's got the correct iteration. Now; how do we get it to start from zero?

x = int(input())
y = 1
for i in range(0,18):
print(x)
x+=y
y+=2