Leap Year?

Question

x = int(input()
def leap_year(x):
if x % 4 == 0:
print(x)
else:
print("nope")

leap_year(x)

Keep getting an error message on line 2? It says error on "def"? I'm defining an input number which, when divided by 4 % == 0: so not sure why error? Any help appreciated:).

Answer 1

Thanks Swim!

Answer 2

Tanks, Swim.

Now they want it in boleen logic? Am I on the right track? Tested out okay.

x = int(input())
print((x) % 4 == 0 and (x) % 100 != 0 and (x) % 400 == 0)

Answer 3

Changed name on stuff to match their request and everything went haywire:(. says shntax error on line 2? Any ideas what?

year = int(raw_input())
def(raw_input):

print ((year) % 4 == 0 or (year) % 100 != 0 or (year) % 400 != 0)