Doubt in switch case

Question

#include<stdio.h>
#include<stdlib.h>

int main()
{
char ch;
while(1)
{

printf("enter char value:");
scanf("%c",&ch);

switch(ch)
{
case 'a': printf("a\n");
break;
case 'b':printf("b\n");
break;
case 'e':exit(0);
break;
default:printf("chose valid char\n");
}
}
}

Output:

enter char value:a
a
enter char value:chose valid char
enter char value:e

--------------------------------
Process exited after 49.66 seconds with return value 0
Press any key to continue . . .

Friends my doubt is ....I have given a as input ....it's fine. But after that, why is it going to default.........?

Answer 1

~ swim ~ and Anna I tried it on my mobile compiler it's executing the default

Answer 2

cxxdriod ~ swim ~

Answer 3

~ swim ~ he is using an infinite loop, that's true, the newline is causing that

Answer 4

please put the code on code play ground and link it here
edit: it seem the while loop triggers that, but I don't actually know why

Answer 5

It reads whatever you enter as a separator and treats it as a char. For example if your input is "a a a e", it will read the first 'a' and execute case 'a'. Then it will read ' ' (the space used as separator) and execute the default case. Then it will read an 'a' again, and another space etc.

Answer 6

I got that output in dev c

Answer 7

No, In PC .....Dev C++

Answer 8

Thank you friends😊