Using __ipow__ in Python

Question

I've been experimenting with Python Magic Methods and I came across __ipow__

So __pow__ can specify a 3rd argument which lets you do a**b%c efficiently by using an inbuilt pow(a,b,c) function. Without the c, you can just do a**b or pow(a,b).

Similarly, for __ipow__, you use a**=b but what is the 3 argument equivalent? I've tried searching online to get no clear answer. Can someone help me in finding how to use the __ipow__ magic method with 3 arguments? Thanks!

Answer 1

https://rszalski.github.io/magicmethods/ good one.

And here simple answer.
https://stackoverflow.com/questions/26684119/JUMP_LINK__&&__python__&&__JUMP_LINK-ipow-how-to-use-the-third-argument

Answer 2

The __i...__ methods are only implemented for mutable data types like lists because they are not returning a new object but are changing the original one. Thus having a modulo doesn't make any sense. I can't imagine how to modulo a list for example. So yes, that parameter seems to be pretty useless.

Answer 3

Kuba Siekierzyński Sorry for pinging you but I feel that you might have an insight into this question, so if possible could you help me?

Answer 4

Николай Шаповаленко so it means that it is useless?