I need help with Java Basics question.

Question

So, I want to write a program that reads an integer between 0 and 1000 and adds all digits in the integer. For example, say the user inputs 222 then the program would add 2+2+2. How would I go about doing this? Here is what I got so far...

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {

Scanner input = new Scanner(System.in);

System.out.print(" Name a whole number between 1 and 1000 :");

double wholeNumber = input.nextDouble();

double extract = wholeNumber % wholeNumber.length;

}
}

Answer 1

First store the integer in a string, let the user input be a string, then split the string, parseInt or parseDouble and then add them all.

Answer 2

String wholeNumberString = input.next();

Answer 3

Here is what I have ...

How do I split the user's answer so that I can add each integer...

say they put 22...

I want the program to do 2 + 2 = 4

Thank You so much!! (:

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {

Scanner input = new Scanner(System.in);

System.out.print(" Name a whole number between 1 and 1000 :");

String wholeNumberString = input.next();

int wholeNumber = Integer.parseInt(wholeNumberString);

System.out.println( "You typed :" + wholeNumber);

int wholeNumber

}
}

Answer 4

What am I doing wrong here?

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {

Scanner input = new Scanner(System.in);

System.out.print(" Name a whole number between 1 and 1000 :");

String wholeNumberString = input.nextString();

Answer 5

- instead of long code you can post here link from sololearn code editor with your saved code, up right there is icon for shared and there for copy to clipboard

- you need loop for() with wholeNumberString.length() as condition
. in loop get digits from number like 1 from number 123456
. you can use wholeNumberString.substring() and then parseInt()
or wholeNumberString.charAt() - 48
. for check you can print this temporary result, in this time
end of loop