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Can someone pls explain the different output in this 2 for loops c++

#include <iostream> using namespace std; int main() { int i; for(i = 0; i < 4; ++i){ for(int j = 0; j < 4; ++j){ i = i + j; cout<<i; //0136 } //cout<<i; //6 } //cout<<i; //7 return 0; }

9th Jul 2019, 10:09 PM
Ben ogegbo
Ben ogegbo  - avatar
1 Réponse
+ 5
In the given code two for loops are nested. The outer one executes 4 time and the one inside executes its statement block :i=i+j; 4 times for each iteration of outer for loop. One may think inner most statements will be executed 4*4 times but this isn't the case as because we are modifying counter of outer for in inner for. Well , I think I'm confusing you here 😅😅. Let's see how it works. first iteration of outerfor i=0; first iteration of innerfor j=0 i=i+j=0+0=0 prints=>0 second iteration of innerfor j=1 i=i+j=0+1=1 prints=>1 third iteration of innerfor j=2 i=i+j=1+2=3 prints=>3 four iteration of innerfor j=3 i=i+j=3+3=6 prints=>6 Now! Innerfor loop breaks!🐒 why? Because j<4 evaluates to false as j=4 now.as it breaks control reaches next statements cout<<i; prints, =>6 i++ =>increments 6 to 7 Outerfor loop checks condition. i<4 ....false. Next statement executed. I. E. cout<<i; prints=>7.
10th Jul 2019, 2:52 AM
🇮🇳Omkar🕉
🇮🇳Omkar🕉 - avatar