How many arguments are in this function call? range(0, 100, 5)

Question

How many arguments are in this function call?
range(0, 100, 5)

Answer 1

The second parameter is the upper limit (in this case = 100), but 100 is not included. so if you run this code:

for i in range(0,10):
print(i, end=', ')
# output is: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,

So if the upper limit has to be included you have to say:

for i in range(0,10 + 1):
print(i, end=', ')
# output is: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

Answer 2

3

Answer 3

ISN'T THE ARGUMENT'S ARE 0(START), 100(STOP) & 5(STEP) ?
BECAUSE THE PROGRAM WILL RUN LIKE 0, 5, 10, 15, 20 TILL 95 .
ANYONE, LET ME KNOW I AM WRONG OR RIGHT PLEASE .

Answer 4

its 3 as they are asking for arguments but the list of numbers

Answer 5

There are 3 arguments in your call to range, 0, 100 and 5. So the function goes from 0 to 100 (not included) with a step size of 5.

So the series you will get is 0,5,10,15 and so on till 95.

Edit: Apologies for the incorrect information earlier.

Answer 6

How many arguments are in this function call? range(0, 100, 5

Answer 7

There are total of 3 arguments.

Answer 8

there are 3

Answer 9

3

Answer 10

3

Answer 11

3

Answer 12

There are total of 3 arguments.

Answer 13

How many arguments are in this function call?
range(0, 100, 5)