what is the value of x after the following code? please explain .

Question

int x=8;
int y=7;
x++;
x+=y--;

Answer 1

16

Answer 2

tnx a lot from my heart

Answer 3

But y-- == 6

Answer 4

16

Answer 5

Need answer

Answer 6

What is the point of the -- after y? It does nothing? Fine x=16 but why have the -- after y? Is there any reason to ever have this code other than in this example?

Answer 7

Hi y friends , here is the explanation
x = 8, y = 7
x++ this value adds 1 to x i.e. ( x = 9 )
x += y-- gives x = x + y-- = 9 + 7 = 16.
Here 'y' value is taken as 7 because y-- is a postfix operation, so the current value of y is used for the calculation and is then decremented.

Answer 8

What is the value of x after this line of code executes?

int x = 9 % 4;

Answer 9

What is value of x after this code
Int x=2
X+=1
X*=2x-=2