X vs y operator

Question

Why is,
int x = 34;
int y = x++;
System.out.println(y);
Output : 34
And
int x = 34;
int y = x++;
System.out.println(x);
Output : 35

Answer 1

Because you safe the valu of x in y and only after that step x gets incrementet by 1

If you would write y = ++x the value will be incrementet first and then it will be saved in y

Answer 2

Because you are using postfix x++ instead of prefix ++x. Postfix increments after assignment prefix increments before.

Answer 3

Because in y first x equal 34 then y equal 35 for this problem chang y = ++x then print y

Answer 4

Because the first one is postfix it gets its incremented value only in next step of the program.And at the second time it saves the value of previous x

Answer 5

because,
the variable x hasnt changed , it is declared as x = 34