Explain it for me, plz. Step by step

Question

w1="welcome"
w2="home"
r=[]
for x in w1:
if x in w2:
r.append(x)
print(r[2]+r[1]+r[2])

---》mom

Answer 1

It checks every letter of "welcome", and adds it to r if it is in "home". So,

w: not in "home"
e: in "home" (r[0])
l: not in "home"
c: not in "home"
o: in "home" (r[1])
m: in "home" (r[2])
e: in "home" (r[3])

The list r containd these four characters: ['e', 'o', 'm', 'e']
So, r[2] + r[1] + r[2] = "mom"

Answer 2

for x in w1 will go through all the values in w1 if the present value is found in w2 put it in r, after the loop we will have "eome" printing r[2] -> m r[1] -> o r[2] -> m will now give you "mom"

Answer 3

the for-loop goes throw the String "welcome". if a Character in "welcome" is present in the String "home" it gets added to the list 'r'.
in the end r is equal to:
["e", "o", "m" "e"]
taking the second, first and second index and adding them up results in "mom"
hope this helped! 😄

Answer 4

The code first creates two strings and an empty list,which can accept new values using append().
From 4th line: for x(it represents the letters in w1 ONE BY ONE so you can use anything like y to replace x) in string w1,if x(representing one letter in w1 at one time) exists in w2,add it to the list. As w1 and w2 contain e,o,m,e(repeated),list=['e','o','m','e']
Index of a list starts from 0. So 'o' is 1st value and 'm' is the second(r[2]).

Answer 5

Thank you