Why the print(2) statement is not printed after raise exception ? Can anyone help me......

Answer 1

Print(1)
raise ValueError
Print(2)

In this code why print(2) is not executed ??

Answer 2

In Python, unhandled exceptions abort the program and all following code is skipped.

You must:
(1) include the code in a guarded snippet:
try: raise ValueError
(2) handle raised exceptions:
except: pass
or
except: print("raised")

This way print(2) will be reached