Logical not operation make me confused

Question

1st case

int a = 100;
void main(){
if(! a>500){
a = 200;
}
printf("%d", a);
}

O/p----> 100

2nd case:

int a = 100;
void main(){
if(! 500<a){
a = 200;
}
printf("%d", a);
}

O/p----> 200

Both the condition are same but why output are not please explain it. I want to know.

Answer 1

It's because it has higher precedence than comparison.

!a →a is true, so it will be false (0)
0 > 500 is false, so the code doesn't execute

!500 → 500 is true, so it will be false (0)
0 < 100 is true, so a will be 200

Answer 2

I have an explanation, but I'm not sure AT ALL it is the good one.

In first case :
!a = 0
0 > 500 //false

In second case
!500 = 0
0 < a //true

Answer 3

Great it's a little bit tricky. Thanks to all to clear my confusion

Answer 4

You are confusing Boolean and numeric operators 🤗

Answer 5

If your trying to 'Not' the whole expression then put brackets round it. e.g.
if(! (a > 500)) {
blah blah blah;
}

Answer 6

Yes, rowdynnejones adding brackets will help clear the confusion caused by operator precedence to get a definite result.