Write a Python function that takes as input a list of integers returns the most occuring and least occuring integers.

Question

For instance>>>
frequency([13,12,11,13,14,13,7,11,13,14,12])
Should return
([7], [13]) >>>frequency([13,12,11,13,14,13,7,11,13,14,12,14,14])
Should return
([7], [13, 14])

Answer 1

show your code to see that you atleast tried

Answer 2

sounds like homework :)

Answer 3

😅

Answer 4

Sourav A.S sorry my brother broke his leg, but hes alright now il check when i wake up

Answer 5

Cat Sauce geez, thats something else. good luck to you and your brother. happy to hear he’s is sort of alright now.

Answer 6

Cat Sauce Thanks alot. I hope
your brother is ok.

Answer 7

Sourav A.S if you can show us a try you made but failed, il be happy to help you :)

Answer 8

def frequency (i):
d=[ ]
d.append(( max(set(i), key=i.count)))
print(d)

Answer 9

It is only for getting most occuring integer, but it doesnt
Work if there are multiple integers occuring most

Answer 10

so you want to check how many times all the integers have occured?

Answer 11

I want know which integers are leat occuring and which are most occuring

Answer 12

For eg:
Fun([1,2,1,3,2])
Should return [3,[1,2]]
Where 3 is the least occuring and 1,2 are the most occuring

Answer 13

wait 1 min and il help

Answer 14

Cat Sauce did you get the code

Answer 15

I'm sure I've seen something similar been done on here before, Look up Counter in collections module in python.org.

Answer 16

I think this does exactly what you need.
from collections import Counter
mylist = [15, 20, 33, 4, 15, 20, 4, 20, 2, 3, 4]
mylist2 = []

for x in mylist:
mylist2.append(str(x)) # had to do the (str), something about the Count function needing hashable.

def get_most_least(x):
most_occuring = []
least_occuring = []
combined_list = []
cnt = Counter(x)
for a, b in cnt.items():
if b == max(cnt.values()):
most_occuring.append(a)
if b == min(cnt.values()):
least_occuring.append(a)
combined_list = [least_occuring, most_occuring]
return combined_list

print(get_most_least(mylist2))