Is the first character of a string also its address?

Question

String

Answer 1

The indexes of the array refer to the addresses if they are not dereferenced.

Run this piece of code and you'll get it.

char arr[] = "Hello";

for(int i = 0; i < 5; i++)
printf("%x\n", arr + i);

Answer 2

no

Answer 3

if the answer is no, what does the address of a string indicate?

Answer 4

where the string is stored in memory

Answer 5

So is the first character? Or the index is signed in " \0 "?

Answer 6

Or maybe there are many byte who include index?

Answer 7

the * operator represents the bits other than the value bits, so the address in memory right?

Answer 8

The name of the array, is a pointer to the first element. So if you don't dereference, you get the adress.

*(a+3) or a[3] are just different ways of dereferencing.

(That's my superficial interpretation that didn't trip me up so far and is hopefully correct enough. ;-))

Answer 9

int main () {   int a [10];   float b [] = {0.12, 3.23, 1.23, 1e2, -12.43};   printf ("a has address =% x and occupies% d bytes n", & a, sizeof (a));   printf ("address of the first element =% x n", & (a [0]));   printf ("bytes occupied by each element =% d n", sizeof (a [1]));   return 0; }