Help please. Write a program error if the user input is an integer or float, or anything that doesn't consist of words .

Question

the input function turns the user input (whether alphabets or numbers into a string so how do I make this program accepts only string values like Henry,jake or Peter. When I run this program and I enter a number or float the statement in the if block still runs. How do I go about this?

name = input('enter your name, alphabets only: ')
if type(name)==str:
print('welcome {}'.format(name))
else:
print('i said alphabets only, what the heck is wrong with you')

Answer 1

https://code.sololearn.com/c6ujjv5T5SY0/?ref=app

Answer 2

rodwynnejones what if it's not a number ? You only considered them to be numbers, when then can be any character: %, €, @...
You need to eliminate them all, and leave letters only, and space character

Answer 3

I'll need to study more then. Thanks for the answers I appreciate 🙏

Answer 4

~ swim ~ I'm already half way through my course in python but I don't recognize any of the function you used . What section is the isaalpha part in?

Answer 5

try this:-
try:
name = input('enter your name, alphabets only: ')
int(name)
print('i said alphabets only, what the heck is wrong with you')
except ValueError:
print('welcome {}'.format(name))

Answer 6

Aymane Boukrouh thanks I just looked it up now. Is there any other way around this apart from the one you used?

Answer 7

Onimisi depends on what you want to do exactly, but if you want to check that there are alphabets only, I don't know any other way to do it other than check each and every character on its own.

Answer 8

Aymane Boukrouh is there any reference material I can read on this subject?

Answer 9

this then
import re
name = input('enter your name, alphabets only: ')
if len(re.findall("[^a-zA-Z ]", name)) == 0:
print('welcome {}'.format(name))
else:
print('i said alphabets only, what the heck is wrong with you')

edited:- space after the 'Z' to allow more than one word.

Answer 10

Onimisi I don't so, this only uses loops and conditions, there might be some frameworks thought, but I don't know any, I just make a def depending on my needs

Answer 11

I suggest you use the regex.

Answer 12

swim
I was looking at you code (hope you don't mind) and it got me thinking...."i wonder if........and yes.....you can:-
print("input accepted" if input('Enter you name').isalpha() else "only alphabets allowed")
(although..... it only accepts one word string)

Answer 13

Thanks ~ swim ~ 🙏🙇

Answer 14

______________________________________
myList = ['1' , '2', '3', '4' ... '9']
for number in myList:
if number not in name:
print()
else:
print("error")
_______________________________________
Ok, this program will solve your problem because floats and intgers bouth contain numbers in string type and, you can add what ever item you want to your list to give error for user if the user enters that item of list.

Answer 15

Hey, you could do something like this

name = str(input ('Digit your name :'))

If name.isalpha():
Print('Hello ...')
Else:
Print('...')

The method isalpha() is a string method that return true if all items in the string are in alphabet, so if the user input some number or any special characters, it will return false and will run what's in the else statement

Good studies man 🙏

Answer 16

Use regular expressions:

import re

pattern = r"[^a-zA-Z]"

if re.search(pattern, some_input):
print("Your input sucks")