string or char*

Question

In my code, why using string doesn't make an exeption and work like char*?
https://code.sololearn.com/cUbLha0LrxeN/?ref=app

Answer 1

Because std::string operator [ ] is no-throw guarantee.
Accessing an element out of bounds is undefined behaviour and may lead to segmentation faults

Answer 2

~ swim ~ Are strings dynamic char arrays?

Answer 3

Thanks!

Answer 4

Check this out,

int main() {
string s;
s[2]='a';
cout<<s[2]<<endl;
}

According to what you said, it shouldn't print anything as the first character is null.
But if you print it by its index, it has output.

Answer 5

Oh, I see. Thanks for clarification.

Answer 6

But i interested where i didn't get index out of range or segmentation fault as exception!

Answer 7

int main() {
string s;
s[2] = 'a';
cout << s[2] << endl;
cout << sizeof(s) << endl;
}

Maybe not, I am getting 32 🤔

Answer 8

But yes, the length function is giving me 0 output.

Answer 9

I have an empty string as output in my system!

Answer 10

Sorry, your code is wrong if you want to print string then you should have
Char s[100] ;
Now you can store any string.