+ 1

My base class has constructor and derive class has default constructor, but it can't compile. Can anyone give me a proper explan

//code is given #include <iostream> using namespace std; class Mother { public: Mother(int a):age(a) { cout<< age; } void sayHi() { cout << "Hi"; } private: int age; }; class Daughter: public Mother { public: Daughter() {}; }; int main() { Daughter d; Mother m(30); d.sayHi(); } //ERROR: no matching function for Mother::Mother()

18th Oct 2019, 1:28 PM
#ArizmaAltair PATHAN
#ArizmaAltair PATHAN - avatar
3 Réponses
+ 2
Add an empty default constructor in 'Mother' class. Mother(){} I can't provide the technical details, OOP is one of my many weaknesses. I'll leave that to those who are more knowledgeable and stronger in OOP.
18th Oct 2019, 1:50 PM
Ipang
0
Give me a proper explanation!? It's not a clear proposition, though program runs as @lpang instruct. But why use double constructor in Mother class? //code give below class Mother { public: Mother(int a):age(a) { cout << age<<endl; cout<< "age mother\n"; } Mother(){}; // Why use another constructor for running void sayHi() { cout << "Hi"; } private: int age; }; class Daughter: public Mother { public: //Default constructor Daughter() { cout <<"daughter age\n"; } }; int main() { Daughter d; //Why not it inherit parameter base constructor Mother m(14); d.sayHi(); }
18th Oct 2019, 2:58 PM
#ArizmaAltair PATHAN
#ArizmaAltair PATHAN - avatar