Why the while loop is working correctly even if the ...

Question

while (num < 6) {
cout << "Number: " << num << endl;
num = num + 1;
}
Here you can see num=num+1 is defined after cout but still the program is working correctly.
C++ operates each and every statement line-wise then why it is showing the correct output.

Answer 1

The "correct" output depends on what you want. Incrementing num before cout will cause the incremented value to be printed instead of the value before being incremented. There is a difference between doing

while (num < 6) {
cout << num;
num = num+1;
}

and

while (num < 6) {
num = num+1;
cout << num;
}

Given that num is initialized as 0, the former prints 012345, while the latter prints 123456.

Answer 2

Ok ok I think the c++ manipulates while loop in such a way that it first check the condition If it is not satisfied then it moves inside and print whatever is given and after printing it, C++ again checks that if the condition is satisfied or not...
That's why the num=num+1 is given at the last, which in first case don't show any change but when while loop prints second time then num= num +1 comes in light....