Why output is llo.

Question

This is c code.

#include<stdio.h>

int main()
{
char *x="hello";
x+=2;
printf("%s",x);
return 0;
}

//Output=llo

Answer 1

char *x is pointer to "hello" so it refers to the starting position of string and when we increment it, then it starts pointing to 2nd char i.e. l.

Answer 2

A char pointer by default points to the 0th index of the character array. So char* x is pointing to h. Then you increment x by 2 so h+1+1 and that is l. So x is now pointing to l and everything from l is printed.

Answer 3

printf("%c",*x);
If you can find the output to this than it would be great.