Print only negative nums its sum applying loop and arrays

Question

I need help with a program, I have to use a loop to output all negative integers and their sum. I should use just basic method.

Negative integers: -2, -1, -7 <----//No comma at the end.

Sum negative nums: -10

When I run my program the last integers has an additional comma at the end, I can’t take it out with “if (i != array.length-1)” because the last element in my array is positive but the loop analyze that there is a empty element. How I can remove that comma in a logical way. The result have to be print inside a loop separate by comma space: (", ").

https://code.sololearn.com/W1amtvybr5d2/?ref=app

Answer 1

I deleted my original comment as I had missed something, but this works:-
function negativeArray(array)
{
document.write("Negative integers: ")
var myarr = [];
for (var i = 0, count = 0; i < array.length; i++)
{
if (array[i] != undefined && array[i] < 0){
myarr.push(array[i]);
count += array[i];
}

}
document.write( "<br>The negative nums: " + myarr);
document.write( "<br>Sum negative nums: " + count);
}
var items = [1, -2, 3, 4- 5, 6, -7, -8];
negativeArray(items);

Answer 2

rodwynnejones Yes array.push is good idea.

Answer 3

Jorge Muñoz This condition (i != array.length-1) will not work in this result because your main array size is 7 and if you check this condition like this suppose

1 != 6 -2 and comma will add
3 != 6 -1 and comma will add
5 != 6 -7 and comma will add

So final array is [-2, -1, -7, ]

Answer 4

rodwynnejones not weird. It's 4 -5. So it's coming -1. I also was wonder first time.

Answer 5

As far as i can see, just remove the if (i != array.length-1) document.write(", ").
I commented out (the above code)...ran it and got the output I was expecting...I must be missing something.
edit....
weird. it's not picking up the -5.
edit again....
ahhh....your missing a comma after the 4.