Skee-ball from Code Coach

Question

Result is error for test 3. What wrong?

https://code.sololearn.com/cJJj828SQ8rv/?ref=app

Answer 1

Russ
It is ok, but why
If a//(b*12)>0:
...
Don,t work?
My be you have a link of article about so type and examples? (length of types)

Answer 2

x=int(input())
y=int(input())
if ((x/12)>=y):
print("Buy it!")
else:
print("Try again")

I code that, and it solves

Answer 3

a / 12 >= b is enough. You not need math.trunc()

Answer 4

Petr

I am not sure but your code does not work for costs = 0.

Answer 5

Russ Denise Roßberg
I think problem is solve. Thank you.

Answer 6

Petr yes, it's possible Denise Roßberg nailed it there - very good point.

Answer 7

Petr here is an alternative

points = int(input())
cost = int(input())
import math
tickets = math.floor(points/12)
if tickets >= cost:
print('Buy it!')
else:
print('Try again')

Answer 8

Russ
I try many variants,f.e.: a//12//b>0, round, other functions of math, but always result is false for test 3. I can not see task for this variant. I try to do this second day...

Answer 9

Russ
Ok

Answer 10

Russ

a=int(input())
b=int(input())
if a-12*b>0:
print("Buy it!")
else:
print("Try again")
Not work

Answer 11

Denise Roßberg
It is only one variant from many other. I mean trunc()...

Answer 12

Russ
I used early variant b==0, and includid it in add if. But it is not change the result

Answer 13

Russ Denise Roßberg
Thank you . I get 5 ok. But i do not like it, couse i don,t understand why my early codes are not right

Answer 14

Has some problems with round(float) in python. If you take round(0.5) it will return 0, round(2.5) return 2. But round(1.5) return 2

Answer 15

Hmm, seems like it *should* work. Maybe it comes down to a rounding error. See if you can modify it to work without dividing.

Answer 16

Petr Like I said, try to do *without* dividing.

Answer 17

Petr Why does it need to be strictly greater than 0?

Answer 18

Petr
And I mean
if a / 12 >= b:
//print
else:
//print

works for all cases.

Answer 19

Ok so you have it now. What I was trying to get you to do was:

if a-12*b>=0:...

the ">=" was the sticking point that you'd missed.

I'm not sure why your original code failed, as I said earlier. I can only assume that case had the *exact* number of points necessary to get the prize, and somehow a rounding error wheb dividing worked its way in. I couldn't find an example to demonstrate it though.

(a/12)//b>0 would fail, whereas (a/12)>=b would work.

Answer 20

Sorry - misread. Again, not sure, sorry.