How To transform a string to a list

Question

Hello
I have a string
A='['s','c','h',.....]'
How To transform To this A=['s','c','h',.....]

Thank you

Answer 1

Atleast you could use eval function.

eval("['1', '8', '9']")
Evaluates to ['1', '8', '9']

But because some developers discourage using of eval function, I'll offer another way:

💩💩💩💩💩💩💩💩💩💩💩💩
💩 💩
💩 A = A[2:-2].split(',') 💩
💩 (this method is 💩) 💩
💩💩💩💩💩💩💩💩💩💩💩💩

Answer 2

Something like this (demo):
https://code.sololearn.com/c0KVuHpstBaL

Answer 3

Alexander You don't need to use list( ).
.split automatically converts the result as list.

But the problem with that method is that the list A contained strings.

You would get a list of strings, where each string gets double amount of quotes.

['1', '2', '3'][1:-1].split(', ')
would evaluate to:
['\'1\'', '\'2\'', '\'3\'']

You could fix it with:
['1', '2', '3'][2:-2].split('\', \'')
And get:
['1', '2', '3']

But the problem is that you might not know:
-How many spaces is used to separate the items.
-Which quotes were used.

Because of those 2 problems using split method would not be good for this problem.

Answer 4

iren yeger A[1:-1] strips the squarebrackets, .split makes the string a list using certain separators. (In the sample it used comma character , as separator, but it could have caused problems, if:
-The items also had ",".
-The items were separated with different amount of spaces.

These would have caused problems with the method:
'["5", "4","3"]' #Different separators ", " and ",".
A[1:-1].split(",") would return ["5", " 4", "3"]

'["8,", "7", "2"]' #An item had ",".
A[1:-1].split(",") would return ["8", ""]
...

Ok it was a bad method.
I think to get a better way than eval, it could require 100 lines code.

Answer 5

consider using a regular expression, promise you... much easier to do. (use re.findall)

Answer 6

iren yeger Is that right?
a='[a, b, c]'
a=list(a[1:-1].split(', '))

Answer 7

Thank you Seb TheS Alexander

Answer 8

Seb TheS Really ... necessary anticipate👍

Answer 9

Just simple with use of slipt function. Split function takes from where you want to slipt it into list as parameter

Answer 10

Seb TheS
Thank you it works.
But please can you explain me what does the second method