Having a problem in Average Word Length(code coach)

Question

import java.util.*;
public class Program
{
public static void main(String[] args)
{
Scanner sc=new Scanner(System.in);
String k=sc.nextLine();
int a=k.length();
int x=0;
for(int i=0;i<a;i++)
{
char s=k.charAt(i);
if(s==33|s==34|s==39|s==44|s==46|s==58|s==59|s==63|s==32)
{
continue;
}
else
{
x++;
}
}
int y=0;
int z=0;
for(int i=0;i<a;i++)
{
if(k.charAt(i)==32)
{
y++;
}
}
z=y+1;
double r=(double)x/z;
int b=0;
if(r==Math.round(r))
{
b=(int)Math.rint(r);
}
else
{
b=((int)Math.rint(r))+1;
}
System.out.print(b);
}
}

Answer 1

s pal
The first part is correct.

Second part: you need to round up. Use Math.ceil().

double r = (double)x/z;
System.out.println((int)Math.ceil(r));

Answer 2

Interesting approach, why did you not use regular expressions In order to remove the punctuation from the String? , therefore attempting to remove characters according to int value seems hard coded and less dynamic.

Attempt regular expressions maybe ? That could be your identification of punctuation in the input String.

Answer 3

s pal I believe it could be because that test case incorporates punctuation that you need taking into account , unless it could be the way in which you are averaging the word length.

Answer 4

All cases work but only the 4 case shows error Justin Joseph

Answer 5

Justin Joseph I think the problem maybe in second part and had earlier tried by eliminating all except alphabets, numbers and space so that all other gets out